Solving Equations

math.solve(equation: txt) -> MathExpr

Solves an equation for its variable. Returns a MathExpr object.

expr = math.solve("2x + 4 = 10")
print(expr.result())   # x = 3

expr = math.solve("x^2 - 5x + 6 = 0")
print(expr.result())   # x = 3, x = 2

Supported equation formats:

• Linear: "2x + 4 = 10", "3x - 12 = 0", "x/2 = 5"
• Quadratic: "x^2 - 5x + 6 = 0", "x^2 - 4 = 0"
• With constants: "pi * r^2 = 100"

MathExpr Object Methods

Method	Returns	Description
.result()	txt	Final solution string
.step(n)	txt	Nth transformation step (0-indexed)
.steps()	array<txt>	All transformation steps
.original()	txt	Original equation string
.variable()	txt	Variable that was solved for

Examples

Linear equation with step-by-step

main() {
    expr = math.solve("3x + 6 = 12")

    for i in 0..expr.steps().len() {
        print(expr.step(i))
    }
    # Step 0: 3x + 6 = 12
    # Step 1: 3x = 6
    # Step 2: x = 2
}

Quadratic formula

main() {
    expr = math.solve("x^2 - 5x + 6 = 0")
    print(expr.result())    # x = 3, x = 2
    print(expr.original())  # x^2 - 5x + 6 = 0
    print(expr.variable())  # x
}